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F(x)=(x-6)^3(x+9)^2 zeroes

User Bschwagg
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Answer: The zeroes of the function
\(f(x) = (x-6)^3(x+9)^2\) are
\(x = 6\) and
\(x = -9\).

Explanation:

The zeroes of a polynomial are the x-values that make the polynomial equal to zero. For the given function
\(f(x) = (x-6)^3(x+9)^2\), the zeroes are the values of x that satisfy the equation
\(f(x) = 0\).

Looking at the factors of the polynomial, we can see that the zeroes are:

-
\(x = 6\), because if we substitute
\(x = 6\) into the function, we get
\((6-6)^3(6+9)^2 = 0\).

-
\(x = -9\), because if we substitute
\(x = -9\) into the function, we get
\((-9-6)^3(-9+9)^2 = 0\).

So, the zeroes of the function
\(f(x) = (x-6)^3(x+9)^2\) are
\(x = 6\) and
\(x = -9\).

User Theunraveler
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