Question

1-27) if f(x) = x² - 1 and g(x) = x + 1, then when x doesnt equal -1, f(x) / g(x) =
helpp

Answer 1

x - 1

Explanation:

Identity used: (a² - b²) = (a + b)(a - b)

Given:

f(x) = x² - 1
g(x) = x + 1

Finding f(x) / g(x):

`\displaystyle (f(x))/(g(x)) = (x^2 - 1)/(x + 1)`

`\displaystyle (f(x))/(g(x)) = ((x + 1)(x - 1))/(x + 1)` (using the property mentioned)

`\displaystyle (f(x))/(g(x)) = (x - 1)` (cancelling (x + 1) from the numerator and denominator)

Hence, f(x) / g(x) = (x - 1)
(where x doesn't equal -1)