Question

If (2 0) is a solution of linear equation 2x-5y=k then find the value of k​

Answer 1

The answer is:

4 = k

Work/explanation:

Since we know the values of both x and y, we can plug them into the equation and solve for k:

`\sf{2x-5y=k}`

`\bf{2(2)-5(0)=k}`

Simplify:

`\bf{4-0=k}`

`\bf{4=k}`

Therefore, k = 4.

`\rule{300pt}{3pt}`

Note : how do we know which number to plug in for x or y?

Well, if we remember the form of a point on the x-y plane, we'll know.

The form of the point is (x,y).

And here we have the point (2,0) where 2 = x and 0 = y.

Answer 2

If (2, 0) is a solution of the linear equation
`\displaystyle\sf 2x - 5y = k`, we can substitute the values of
`\displaystyle\sf x = 2` and
`\displaystyle\sf y = 0` into the equation to find the value of
`\displaystyle\sf k`.

Substituting
`\displaystyle\sf x = 2` and
`\displaystyle\sf y = 0` into the equation, we get:

`\displaystyle\sf 2(2) - 5(0) = k`

Simplifying:

`\displaystyle\sf 4 - 0 = k`

`\displaystyle\sf 4 = k`

Therefore, the value of
`\displaystyle\sf k` is 4 when (2, 0) is a solution of the linear equation
`\displaystyle\sf 2x - 5y = k`.