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Find a function whose graph is a parabola with vertex (3, -2) and that passes through the point (4, 3).

I don't understand can someone help please​

User MillerC
by
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1 Answer

1 vote

Answer:


y=5(x-3)^2+2

Explanation:


y=a(x-h)^2+k\\y=a(x-3)^2-2\\\\3=a(4-3)^2-2\\3=a(1)^2-2\\3=a-2\\5=a\\\\y=5(x-3)^2+2

By using the vertex form of a parabola, we were able to plug in the vertex (h,k)=(3,-2) and then eventually our point (x,y)=(4,3) to solve for "a" to get the final function.

User Anbarasan
by
8.3k points

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