Answer:
3600
Explanation:
if it is divisible by 2 then the number at the end must be also divisible by 2, so 0;2;4;6;8 can't be at the end of the number.
if it is divisible by 5 then the number at the end must be also divisible by 5, so 0 and 5 can't be at the end of the number.
now at the first digit we can have all the numbers from 1 to 9 (0 can't be the first number), so there are 9 options
at the second and third digit we can have all the numbers from 0 to 9, so there are 10 options
and at the last digit we can only have 1;3;7;9 so there are only 4 options.
and that makes it:
