Final answer:
The coefficient of static friction needed in Part A depends on the equalization of the maximum static friction force and spring force when the glider stops. For Part B, the maximum initial speed of the glider can be given by equating the initial kinetic energy to the work done by static friction using the given static friction coefficient of 0.70.
Step-by-step explanation:
To solve for the coefficient of static friction needed to prevent the glider from moving back (Part A), we first need to understand what forces are acting on the glider. When the glider stops, the spring force, which tends to pull it back to the left, must be equal to the maximum static friction force for it to remain at rest. The spring force at maximum compression or extension can be calculated using Hooke's Law (F = kx), where k is the spring constant (20.0 N/m) and x is the maximum displacement. This displacement is unknown, but we can infer from the condition that the glider stops instantaneously that we're interested in the initial stopping point. The maximum static friction force can be expressed as Fs_max = μ_s * N, where μ_s is the coefficient of static friction we wish to find and N is the normal force, which is equal to the weight of the glider for a horizontal surface.
For Part B, with a given coefficient of static friction of 0.70, the question is asking for the maximum initial speed at which the glider can move without overcoming the maximum static friction when it momentarily stops. To find this, we need to consider energy conservation and the work done by friction. The work done by the kinetic friction force (which opposes the glider's motion) will decrease the kinetic energy of the glider. The maximum amount of kinetic energy that can be converted to work done by static friction without causing motion is given by the equation W = Fs_max * x. Using this relationship, we can set the initial kinetic energy (1/2)*m*v_1^2) equal to the maximum work done by static friction to solve for v_1.