Answer:
CB = 30.15
Explanation:
180-58-93 = 29 degrees for angle B
draw a line perpendicular to BC down to point A, lets call the perpendicular point D.
now you've got 2 similar, smaller triangles
angle A is split into two angles, 29 degrees above and 58 degrees below.
sin 29 =CD/16
CD = 7.75
cos 29 = AD/16
AD = 14
tan 58 =DB/AD = DB/14
DB = 22.40
CD + DB = 7.75 + 22.40 = 30.15