Question

ABC is a isosceles triangle. is AD the height of ABC? Explain.

(Yes or No) _ AD is (Perpendicular or not) _ to BC because _ A. 28^2 + 45^2 = 53^2
B. 28^2 + 53^2 ≠ 45^2
C. 28^2 + 45^2 ≠ 53^2
D. 28^2 + 53^2 = 45^2

The things in () are answers to fill the "_"

Answer 1

Step-by-step explanation:

AD is the height of BC

Since 28^2+45^2=53^2

Therefore AD is perpendicular to BC.

The perpendicular bisector of an isosceles triangle is also the median of the triangle.

Therefore BD=DC=28

Therefore AB=AC=53

Answer 2

No, AD is not the height of ABC because 28^2 + 45^2 ≠ 53^2.

Step-by-step explanation:

An isosceles triangle has two sides of equal length and two equal angles opposite those sides. The height of a triangle is a line segment perpendicular to the base that connects the base to the opposite vertex.

To determine if AD is the height of triangle ABC, we need to check if AD is perpendicular to BC. We can use the Pythagorean theorem to determine this.

Answer: No. AD is not perpendicular to BC. Option C, 28^2 + 45^2 ≠ 53^2, is correct. This means that AD is not the height of triangle ABC.