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Subtract the sum of 12ab-10b²-18a² and 9ab+12b²+14a² from ab+2b² and 3b²-a²​

1 Answer

6 votes

Answer:

3a² + 3b² - 20ab

Explanation:

Sum of 12ab-10b²-18a² and 9ab+12b²+14a²

12ab - 10b² - 18a² + 9ab + 12b² + 14a²

= 14a² - 18a² + 12b² - 10b² + 12ab + 9ab

= -4a² + 2b² + 21ab

Sum of ab + 2b² and 3b²- a²

= ab + 2b² + 3b²- a²

= -a² + 2b² + 3b² + ab

= -a² + 5b² + ab

Subtract

-a² + 5b² + ab - (-4a² + 2b² + 21ab

)

= -a² + 5b² + ab + 4a² - 2b² - 21ab

= 3a² + 3b² - 20ab

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