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A gas occupies 505 cm' at STP. A weather change reduces volume to 710 cm?, calculate the temperature.

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Answer:

Temperature = 382.913 Kelvin

Step-by-step explanation:

To calculate the temperature, use the ideal gas law:-

PV = nRT

Here
- P stands for Pressure, measured in atm.
- V stands for Volume, measured in liters.
- n represents the Number of moles.
- R is the Ideal gas constant, with a value of 0.0821 L·atm/(mol·K).
- T stands for Temperature, measured in Kelvin.

The conditions defined as STP (Standard Temperature and Pressure) consist of a temperature of 273.15 Kelvin (equivalent to 0 degrees Celsius) and a pressure of 1 atmosphere.

We Have

Initial volume (V1) = 505 cm³

Final volume (V2) = 710 cm³

Initial temperature (T1) = 273.15 K (STP)

First, convert the volumes to liters:

V1 = 505 cm³ = 505/1000 L = 0.505 L

V2 = 710 cm³ = 710/1000 L = 0.710 L

Pressure and the number of moles are constant, we can write the equation as:

V1/T1 = V2/T2

Solving for T2:

T2 = (V2 * T1) / V1

T2 = (0.710 L * 273.15 K) / 0.505 L

On Solving the equation :-

T2 = 383.913 K (Approx)

Based on the weather change, the gas temperature is estimated to be around 383.913 Kelvin.

User Rachit Tayal
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