Question

Suppose you add 2.4x10^-3 moles of HNO3 to enough water to make 792 mL of solution What is the pH of the solution?

URGENT

Answer 1

First, we need to find the number of moles of HNO3 in the solution:

2.4 x 10^-3 moles HNO3 / 0.792 L solution = 0.00303 M HNO3

Since HNO3 is a strong acid, it will dissociate completely in solution to form H+ and NO3- ions. Therefore, the concentration of H+ ions in the solution is also 0.00303 M.

To find the pH of the solution, we can use the formula:

pH = -log[H+]

pH = -log(0.00303)

pH = 2.52

Therefore, the pH of the solution is 2.52.