From the balanced chemical equation, we can see that 1 mole of iron ore reacts with 110/4 = 27.5 moles of oxygen and produces 2 moles of iron oxide.
Therefore, to react completely with 2,512.0 moles of iron ore, we need 2,512.0 x 27.5 = 69,080 moles of oxygen.
And the number of moles of iron oxide produced will be (2/4) x 2,512.0 = 1,256.0 moles.