Question

What are the zeros of the function? f(x)=x2+9x−36

Answer 1

To find the zeros of the function f(x) = x^2 + 9x - 36, we need to solve for x when f(x) = 0.

We can use the quadratic formula to solve for x:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

In this case, a = 1, b = 9, and c = -36.

x = (-9 ± sqrt(9^2 - 4(1)(-36))) / 2(1)

x = (-9 ± sqrt(441)) / 2

x = (-9 ± 21) / 2

So the zeros of the function are x = -6 and x = 3.

Answer 2

x = -12 and x = 3

Explanation:

The equation f(x) = 0 must be solved in order to determine the zeros of the function f(x) = x2 + 9x - 36. By factoring, solving the square, or applying the quadratic formula, we can accomplish this.

Let's solve the quadratic problem by factoring:

x^2 + 9x - 36 = 0

(x + 12)(x - 3) = 0

Setting each variable's value to 0

x + 12 = 0 or x - 3 = 0

In each equation, find x.

x = -12 or x = 3

Consequently, x = -12 and x = 3 are the zeros of the function f(x) = x2 + 9x - 36.