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Gas law practice problems

LE
gas
A 3.0L sample of carbon dioxide gas at 155 kPa is injected into a 5.0 L vessel. What is the new pressure of the
gas

2 Answers

6 votes

Final answer:

The final pressure of the gas is 93 kPa.

Step-by-step explanation:

According to Boyle's law, the pressure and volume of a gas are inversely proportional when temperature is held constant. In this case, the initial volume of the gas is 3.0L at a pressure of 155 kPa. When the gas is injected into the 5.0L vessel, the volume increases and the pressure decreases, but the product of the pressure and volume remains constant. Using the equation:

(Initial pressure) x (Initial volume) = (Final pressure) x (Final volume)

We can solve for the final pressure:

(155 kPa) x (3.0L) = (Final pressure) x (5.0L)

Solving for the final pressure gives:

Final pressure = (155 kPa) x (3.0L) / (5.0L) = 93 kPa

User WB Lee
by
3.9k points
8 votes

Answer:

93 kPa

Step-by-step explanation:

Step 1: Given data

  • Initial volume of carbon dioxide gas (V₁): 3.0 L
  • Initial pressure of carbon dioxide gas (P₁): 155 kPa
  • Final volume of carbon dioxide gas (V₂): 5.0 L
  • Final pressure of carbon dioxide gas (P₂): ?

Step 2: Calculate the final pressure of carbon dioxide gas

If we assume carbon dioxide behaves as an ideal gas, we can calculate the final pressure of carbon dioxide gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

P₂ = P₁ × V₁/V₂

P₂ = 155 kPa × 3.0 L/5.0 L = 93 kPa

User Mara
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4.3k points