Question

A.

b.
Each spinner below is spun once. Find the
probability of each event.
C.
Green Blue
Yellow
Red
Yellow
Blue
Blue Green
9
8
7
10 1
Express each answer as a fraction in simplest form.
6
5
2
4
3
a) P(blue, then even)
b) P(not red, then less than 7)
c) P(green, then at least 3)

Answer 1

a) P(blue, then even) = 3/8

b) P(not red, then less than 7) = 9/20

c) P(green, then at least 3) = 1/10

Explanation:

a) The probability of getting blue on the first spinner is 3/4, and the probability of getting an even number on the second spinner is 2/4 or 1/2 since there are two even numbers (4 and 8) out of four possible outcomes. So, the probability of getting blue, then even is:

P(blue, then even) = P(blue) × P(even | blue) = (3/4) × (1/2) = 3/8

b) The probability of not getting red on the first spinner is 3/4 since there are three non-red colors out of four. The probability of getting a number less than 7 on the second spinner is 6/10 or 3/5 since there are six possible outcomes (1, 2, 3, 4, 5, 6) out of ten that satisfy this condition. So, the probability of not getting red, then less than 7 is:

P(not red, then less than 7) = P(not red) × P(less than 7 | not red) = (3/4) × (3/5) = 9/20

c) The probability of getting green on the first spinner is 1/4. The probability of getting a number at least 3 on the second spinner is 4/10 or 2/5 since there are four possible outcomes (3, 4, 5, 6) out of ten that satisfy this condition. So, the probability of getting green, then at least 3 is:

P(green, then at least 3) = P(green) × P(at least 3 | green) = (1/4) × (2/5) = 1/10

Therefore, the probabilities are:

a) P(blue, then even) = 3/8

b) P(not red, then less than 7) = 9/20

c) P(green, then at least 3) = 1/10

(Refrence to chatgpts work)