Answer:
a) P(blue, then even) = 3/8
b) P(not red, then less than 7) = 9/20
c) P(green, then at least 3) = 1/10
Explanation:
a) The probability of getting blue on the first spinner is 3/4, and the probability of getting an even number on the second spinner is 2/4 or 1/2 since there are two even numbers (4 and 8) out of four possible outcomes. So, the probability of getting blue, then even is:
P(blue, then even) = P(blue) × P(even | blue) = (3/4) × (1/2) = 3/8
b) The probability of not getting red on the first spinner is 3/4 since there are three non-red colors out of four. The probability of getting a number less than 7 on the second spinner is 6/10 or 3/5 since there are six possible outcomes (1, 2, 3, 4, 5, 6) out of ten that satisfy this condition. So, the probability of not getting red, then less than 7 is:
P(not red, then less than 7) = P(not red) × P(less than 7 | not red) = (3/4) × (3/5) = 9/20
c) The probability of getting green on the first spinner is 1/4. The probability of getting a number at least 3 on the second spinner is 4/10 or 2/5 since there are four possible outcomes (3, 4, 5, 6) out of ten that satisfy this condition. So, the probability of getting green, then at least 3 is:
P(green, then at least 3) = P(green) × P(at least 3 | green) = (1/4) × (2/5) = 1/10
Therefore, the probabilities are:
a) P(blue, then even) = 3/8
b) P(not red, then less than 7) = 9/20
c) P(green, then at least 3) = 1/10
(Refrence to chatgpts work)