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Simplify

Square root of x^2-8x+16 if x<4

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Answer:

the simplified expression for √(x^2 - 8x + 16) when x < 4 is | x - 4 |.

Explanation:

Given the expression √(x^2 - 8x + 16), we notice that the expression under the square root is a quadratic. Let's try to factor it:

x^2 - 8x + 16

This quadratic can be factored as a perfect square trinomial:

(x - 4)^2

Now we have the expression:

√((x - 4)^2)

When simplifying the square root of a square, we need to consider the domain of the variable. Since x < 4, the expression (x - 4) will always be negative or equal to zero. Therefore, when we simplify the square root, we should take the absolute value of (x - 4) to ensure that the result is non-negative:

| x - 4 |

User Sankar Guru
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