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The coordinates of Triangle ABC are A= (-1.1). B (3,-5) and C (3, 3). What is the area of the triangle?

User Sunchezz
by
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1 Answer

5 votes

Answer:

  • 16 square units

-----------------------------

We are given the vertices:

  • A= (-1.1). B (3,-5) and C (3, 3)

Use the formula:

  • A = (1/2) * |(x₁ * (y₂ - y₃) + x₂ * (y₃ - y₁) + x₃ * (y₁ - y₂))|

Plug in the coordinates of the vertices:

  • A =
  • (1/2) * |((-1) * (-5 - 3) + 3 * (3 - 1) + 3 * (1 - (-5)))| =
  • (1/2) * |(-1 * (-8) + 3 * (2) + 3 * (6))| =
  • (1/2) * |(8 + 6 + 18)| =
  • (1/2) * (32) =
  • 16

So, the area of triangle is 16 square units.

User Bomin
by
8.4k points

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