Question

The coordinates of Triangle ABC are A= (-1.1). B (3,-5) and C (3, 3). What is the area of the triangle?

Answer 1

• 16 square units

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We are given the vertices:

• A= (-1.1). B (3,-5) and C (3, 3)

Use the formula:

• A = (1/2) * |(x₁ * (y₂ - y₃) + x₂ * (y₃ - y₁) + x₃ * (y₁ - y₂))|

Plug in the coordinates of the vertices:

• A =
• (1/2) * |((-1) * (-5 - 3) + 3 * (3 - 1) + 3 * (1 - (-5)))| =
• (1/2) * |(-1 * (-8) + 3 * (2) + 3 * (6))| =
• (1/2) * |(8 + 6 + 18)| =
• (1/2) * (32) =
• 16

So, the area of triangle is 16 square units.