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A bag contains tiles number 1-10. What is the probability of first selecting a PRIME number, replacing it, then selecting a number less than or equal to 3?​

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Answer:

0.12 = 12% probability of first selecting a PRIME number, replacing it, then selecting a number less than or equal to 3

Explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability of independent events:

Suppose we have two events, A and B, that are independent. The probability of both happening is given by:


P(A \cap B) = P(A) * P(B)

In this question:

Event A: Selecting a prime number.

Event B: Selecting a number less than or equal to 3

Probability of selecting a prime number:

Between 1 and 10, we have 4 prime numbers(2,3, 5 and 7), out of 10. So


P(A) = (4)/(10)

Probability of selecting a number less than or equal to 3:

Three numbers(1,2,3) out of 10. So


P(B) = (3)/(10)

Probability of both:


P(A \cap B) = P(A) * P(B) = (4)/(10) * (3)/(10) = (12)/(100) = 0.12

0.12 = 12% probability of first selecting a PRIME number, replacing it, then selecting a number less than or equal to 3

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