Answer:24.66 inches.
Explanation:
Let's start by using algebra to set up a system of equations to represent the given information.
Let L be the length of the rectangle and W be the width of the rectangle.
From the problem, we know that:
The perimeter of the rectangle is 78 inches, which means that 2L + 2W = 78.
The width is 4 less than twice the length, which means that W = 2L - 4.
We can use the second equation to substitute W in terms of L in the first equation, and solve for L:
2L + 2(2L - 4) = 78
2L + 4L - 8 = 78
6L = 86
L = 14.33 (rounded to 2 decimal places)
Now that we know the length, we can use the second equation to find the width:
W = 2L - 4 = 2(14.33) - 4 = 24.66 (rounded to two decimal places)
Therefore, the width of the rectangle is approximately 24.66 inches.