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Sphere !of mass mand sphere 2 of mass Zm hang from light strings Sphere 1is pulled back as shown above, and released from point rest. Sphere has kinetic energy Ki immediately before colliding with sphere 2 . The two spheres stick together and move horizontally for an instant after the collision: During the collision; how does the kinetic energy AK of the sphere system change? tWo 2m Before Release Immediately After Collision it doesnt it loses 1/3 of the initial kinetic energy it loses 1/2 of the initial kinetic energy It loses 2/3 of tre initial kinetic energy

User Gonutz
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Final answer:

During a perfectly inelastic collision, kinetic energy decreases although momentum is conserved. Calculations comparing initial and final kinetic energies after collision, where objects stick together and move as one, reveal this loss of kinetic energy.

Step-by-step explanation:

When two spheres or objects collide and stick together, such a collision is known as a perfectly inelastic collision. In such collisions, momentum is conserved, but kinetic energy is not; it is, in fact, reduced. Given the two examples involving Sphere 1 of mass m and Sphere 2 of mass 2m, the kinetic energy Ki will decrease during the collision because the objects stick together and move as one. By using the conservation of momentum and given velocities, one can find the final velocity of the combined mass. Then, the initial kinetic energy can be compared to the final kinetic energy to determine the change in kinetic energy.

To compute the kinetic energy change using a specific example, we consider Mass A (2.0 kg) at 15 m/s colliding with Mass B (4.0 kg) at 7.0 m/s. After the collision, they stick together and move as a single object. Calculations would show that the resulting kinetic energy of the two objects together is less than the sum of their kinetic energies before the collision, due to energy lost to sound, heat, and other forms of non-mechanical energy.

User Andiih
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