Answer:
To solve this problem, we need to use stoichiometry, which is a way to relate the amounts of reactants and products in a chemical reaction.
The balanced equation for the reaction of glucose (C6H12O6) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is:
C6H12O6 + 6O2 → 6CO2 + 6H2O
From the equation, we can see that for every 1 mole of glucose, 6 moles of CO2 are produced. Therefore, we can calculate the amount of glucose produced from the given amount of CO2 as follows:
18.6 moles CO2 x (1 mole C6H12O6 / 6 moles CO2) = 3.10 moles C6H12O6
Now, we need to convert the amount of H2O given in grams to moles, using the molar mass of water:
2.38 x 102 g H2O x (1 mole H2O / 18.015 g H2O) = 13.2 moles H2O
From the equation, we can see that for every 1 mole of glucose, 6 moles of H2O are produced. Therefore, the amount of glucose produced from the given amount of H2O is:
13.2 moles H2O x (1 mole C6H12O6 / 6 moles H2O) = 2.20 moles C6H12O6
Therefore, the maximum amount of glucose that can be produced is 3.10 moles or 2.20 moles, depending on which reactant limits the reaction.
Step-by-step explanation: