Answer:
Step-by-step explanation:
In a gaseous reaction mixture partial pressure is proportion to mole of the gas concerned .
Pressure of the reactant gas from gas equation
PV = nRT
P = nRT / V
= .166 x .082 x ( 273+179) / 10
= .615 atm
C₃H₇OH = (CH₃)₂CO + H₂
before reaction moles in terms of pressure
.615 0 0
After reaction
.615 - x x x
.444 = x² / ( .615 - x )
.273 - .444 x = x²
x² + .444 x - .273 = 0
x = .361 atm
So partial pressure of acetone is .361 atm at equilibrium.