Final answer:
The mass of platinum that could be plated from a Pt(NO3)2 solution using a current of 0.500 A for 55.0 s is 0.00139 g.
Step-by-step explanation:
To calculate the mass of platinum that could be plated on an electrode from the electrolysis of Pt(NO3)2 solution with a current of 0.500 A for 55.0 s, we first need to determine the number of moles of electrons that passed through the cell using the equation:
I = q/t
where I is the current in amperes, q is the charge in coulombs, and t is the time in seconds.
The total charge, q, is:
q = I × t
0.500 A × 55.0 s = 27.5 C
Then, we convert the charge to moles of electrons:
27.5 C × (1 mole e− / 96500 C) = 2.85 x 10−5 moles e−
Knowing the moles of electrons and the fact that platinum's charge during electrolysis is +4, we can find the moles of platinum plated:
2.85 x 10−5 moles e− / 4 e− per Pt = 7.13 x 10−6 moles Pt
Finally, we find the mass of platinum plated by multiplying the moles of platinum by its molar mass (195.08 g/mol):
7.13 x 10−6 moles Pt × 195.08 g/mol = 0.00139 g Pt
Therefore, the mass of platinum that could be plated is 0.00139 g.