Question

You have a 2.0 L balloon filled with air at a temperature of 273 K.

When the volume of the balloon increases to 2.4 L, what is the new temperature?


240 K

323 K

655 K

900 K

Answer 1

• V1=2L
• V2=2.4L
• T1=273K
• T2=?

Apply Charles law

`\\ \rm\Rrightarrow V_1T_2=V_2T_1`

`\\ \rm\Rrightarrow 2T_2=2.4(273)`

`\\ \rm\Rrightarrow 2T_2=655.2`

`\\ \rm\Rrightarrow T_2=(655.2)/(2)`

`\\ \rm\Rrightarrow T_2=327.6K`