Question

determine the volume of the stock solution that should be diluted in order to make 200. ml of 0.069 m sodium benzoate.

Answer 1

17 mL

Step-by-step explanation:

Since from an earlier part of the question we know that the concentration of sodium benzoate is 0.800M, we can use the equation M1V1=M2V2 to figure out the volume. So 0.800*V1=0.069*200. So V1 is equal to 17.25 mL or 17mL since 2 sig figs.

Answer 2

Step-by-step explanation:

200×0.069

13.8×1000

0.0138