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A reaction between 1.7 moles of zinc iodide and excess sodium
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A reaction between 1.7 moles of zinc iodide and excess sodium

User Ens
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Answer: I got you fam

Step-by-step explanation:

The formula is Na2CO3 + ZnI2 → 2NaI + ZnCO3

Or -5.19

User Florian Lopes
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