A reaction between 1.7 moles of zinc iodide and excess sodium

asked Jul 13, 2024 62.7k views

3 votes

by Ens

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4 votes

Answer: I got you fam

Step-by-step explanation:

The formula is Na2CO3 + ZnI2 → 2NaI + ZnCO3

Or -5.19

Florian Lopes answered Jul 17, 2024

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