Question

13 Which polynomial is twice the sum of 4x^2-x + 1 and -6x^2 + x - 4?

(3)-4x²-6
(4)-2x²+x-5
(1)-2r²-3
(2)-41²-3

Answer 1

Answer: is option (3) -4x²-6.

Step-by-step explanation: First, we need to add the two given polynomials:

4x^2 - x + 1 + (-6x^2 + x - 4) = -2x^2 - 3

Now, we need to multiply this sum by 2:

2(-2x^2 - 3) = -4x^2 - 6

Therefore, the polynomial that is twice the sum of 4x^2-x+1 and -6x^2+x-4

Answer 2

The polynomial that is twice the sum of 4x^2 - x + 1 and -6x^2 + x - 4 is -4x^2 - 6. Therefore, the correct option is (3) -4x^2 - 6.

To find the polynomial that is twice the sum of 4x^2 - x + 1 and -6x^2 + x - 4, we first calculate the sum of these two polynomials and then multiply the result by 2.

`\text{Sum} &= (4x^2 - x + 1) + (-6x^2 + x - 4) \\&= 4x^2 - x + 1 - 6x^2 + x - 4 \\&= -2x^2 - 3.`

Now, multiply the sum by 2:

2(-2x^2 - 3) =
`-4x^2` - 6.

So, the correct option is (3)
`-4x^2 - 6`.