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A deli wraps its cylindrical containers of hot food items with plastic wrap. The containers have a diameter of 5.5 inches and a height of 3 inches. What is the minimum amount of plastic wrap needed to completely wrap 8 containers? Round your answer to the nearest tenth and approximate using π = 3.14.

User Cquezel
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2 Answers

3 votes

Answer:

B

Explanation:

User AlexanderNajafi
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3 votes
To calculate the minimum amount of plastic wrap needed to completely wrap 8 cylindrical containers, we need to calculate the total surface area of the 8 containers.

The formula for the surface area of a cylinder is:

A = 2πr^2 + 2πrh

where r is the radius of the base of the cylinder (which is half the diameter), h is the height of the cylinder, and π is approximately equal to 3.14.

To find the total surface area of 8 containers, we can first calculate the surface area of one container and then multiply by 8:

r = 5.5 / 2 = 2.75 inches
h = 3 inches

A = 2π(2.75)^2 + 2π(2.75)(3) = 81.85 square inches

The total surface area of 8 containers is:

8A = 8(81.85) = 654.8 square inches

Therefore, the minimum amount of plastic wrap needed to completely wrap 8 cylindrical containers is approximately 654.8 square inches, rounded to the nearest tenth.
User Yeo
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