Question

A 0.80kg block of carbon (solid) is dropped into 1.4kg of water. If the carbon starts at -20C, the water starts at 92C, and they have equal final temperatures, what is the final temperature of the system?

Answer 1

data given

mass of block(m1) 0.8kg

mass of water (m2) 1.4kg

initial temperature of block (t1) -20c

initial temperature of water (t2) 92c

Required final temperature

Step-by-step explanation:

m1c1w=m2c2w

where

m mass

c is specific heating capacity

w is change of temperature

c of water is 4200

c of carbon is840

0.8×(x+20)×840=1.4×(92-x)×4200

54o960-13440=(672+5880)

527520/6552=6552x/6552

x=80.5

:. final temperature 80.5c