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What volume, in dL, of a 0.421 M Li₃PO₄ solution contains 86.4 g of Li₃PO₄?

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1 Answer

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Answer:

volume= 1.77dL

first you'll find the moles using

Moles= Mass/Molar mass

After that you'll find the volume using

Molarity= Moles/Volume

What volume, in dL, of a 0.421 M Li₃PO₄ solution contains 86.4 g of Li₃PO₄? Answer-example-1
User Jason McFarlane
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