Question

an aircraft passes directly over you with a speed of 900 km/h at an altitude of 10 000 m. what is the angular velocity of the aircraft (relative to you) when directly overhead? three minutes later?

Answer 1

Okay, let's break this down step-by-step:

1) Aircraft speed = 900 km/h = 250 m/s

2) Altitude = 10,000 m

3) When directly overhead:

- Angular velocity = (Velocity) / (Distance) = (250 m/s) / (10,000 m altitude) = 0.025 rad/s

4) 3 minutes later:

- Aircraft will have moved 10,000 * (3/60) = 500 m away from your position

- New distance from you = 10,500 m

- New angular velocity = (250 m/s) / (10,500 m) = 0.024 rad/s

So in summary:

- When directly overhead: Angular velocity = 0.025 rad/s

- 3 minutes later: Angular velocity = 0.024 rad/s

Let me know if you have any other questions!