Answer:
c. 50(i-0.1)² + 210(i - 0.1) + 320.5.
Explanation:
To find the equivalent expression that contains the future value for a monthly interest rate of i = 0.1, we simply substitute i = 0.1 into the equation V = 50(1 + i)² + 100(1 + i) + 150 and simplify.
V = 50(1 + 0.1)² + 100(1 + 0.1) + 150
V = 50(1.1)² + 100(1.1) + 150
V = 50(1.21) + 110 + 150
V = 60.5 + 110 + 150
V = 320.5
Therefore, the expression that contains the future value for a monthly interest rate of i = 0.1 is c. 50(i-0.1)² + 210(i - 0.1) + 320.5.