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8 votes
8 votes
If h<0 and y = 5 in the following equation,
what is the value of h?
√3h²-2-y=0

User Sareesh Krishnan
by
2.7k points

1 Answer

9 votes
9 votes

To solve this equation, you will need to isolate the variable h on one side of the equation. To do this, you can start by adding 2 and y to both sides of the equation to get rid of the constants on the right side:

√3h² - 2 - y = 0

√3h² - 2 + 2 + y = 0 + 2 + y

√3h² = 2 + y

Next, you can square both sides of the equation to eliminate the square root on the left side:

(√3h²)² = (2 + y)²

3h² = 4 + 4y + y²

Then, you can rearrange the terms on the right side to get the equation in standard form:

3h² = 4 + 4y + y²

3h² = (4 + y)(1 + y)

Finally, you can divide both sides of the equation by 3 to isolate the variable h:

h² = (4 + y)/3

Since y is given as 5, you can substitute this value into the equation to find the value of h:

h² = (4 + 5)/3

h² = 9/3

h = √(9/3)

Since h is less than 0, the value of h must be negative.

Therefore, the value of h is -√(9/3).

User Azad Salahli
by
2.6k points
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