Answer: -2
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Step-by-step explanation:
Plug n = 2 into the 2nd equation. We'll involve f(1) = 2.
f(n)=f(n-1)^2-3
f(2) = [ f(2-1) ]^2-3
f(2) = [ f(1) ]^2 - 3
f(2) = (2)^2 - 3 .... replace f(1) with 2; since f(1) = 2
f(2) = 4 - 3
f(2) = 1
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For the last group of steps, we plug in n = 3.
We'll involve f(2) = 1.
f(n) = [ f(n-1) ]^2-3
f(3) = [ f(3-1) ]^2 - 3
f(3) = [ f(2) ]^2 - 3
f(3) = (1)^2 - 3
f(3) = 1 - 3
f(3) = -2 which is the final answer