Question

I need to find the equation of the line shown please help

Answer 1

to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below

`(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{(-6)}}}{\underset{\textit{\large run}} {\underset{x_2}{4}-\underset{x_1}{(-3)}}} \implies \cfrac{8 +6}{4 +3} \implies \cfrac{ 14 }{ 7 } \implies 2`

`\begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{ 2}(x-\stackrel{x_1}{(-3)}) \implies y +6 = 2 ( x +3) \\\\\\ y+6=2x+6\implies {\Large \begin{array}{llll} y=2x \end{array}}`

Answer 2

Answer: y=2x+0

Explanation: this is a linear equation , the equation for this is y=mx+b.
you can find 2 pretty points and do y2-y1/x2-x1
For y-intercept you look at where the line meets the y axis

Work: