Question

28.5 g of iron shot is added to a graduated cylinder containing 45.50 mL of water. The water level rises to the 49.10 mL mark. From this information, calculate the density of iron.

Answer 1

7.92 g/cm^3

Step-by-step explanation:

1 mL = 1 cm^3

density = mass/volume

volume: 49.10 mL - 45.50 mL = 3.60 mL = 3.60 cm^3

mass: 28.5 g

density = (28.5 g)/(3.60 cm^3) = 7.91666... g/cm^3

Answer: 7.92 g/cm^3

Answer 2

Density=mass/volume.

1) we have to calculate the iron volume in liters.

iron volume=second level - first level=49.10 ml-45.50 ml=3.6 ml

3.6 ml=3.6 ml(1 liter / 1000 ml)=0.0036 liters

2) we calculate the mass iron in kg.

28.5 g=28.5 g(1 kg /1000 g)=0.0285 kg.

2) we calculate the density of iron.

density=0.0285 kg / 0.0036 liters=7.92 kg/L

7.92 kg/l=7.92 kg/L(1000 g/1Kg)(1000 cm³/1 L)=7.92 g/cm³.

From this information the Iron density is 7.92 Kg/L or 7.92 g/cm³.

Explanation:

I hope this helps u! :D