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Solve the systems by elimination.
10x + 10y = 40
5x + 3y = 8

1 Answer

3 votes

Answer:

x = -2, y = 6

Explanation:

First, find the opposite of 10 by multiplying 5x+3y=8 by -2 to eliminate 10x.

10x+10y=40

-2(5x+3y=8)

10x+10y=40

-10x-6y=-16 (Subtract 10y - 6y) (Subtract 40 - 16)

4y = 24 (Divide by 4 on both sides)

y = 6

Substitute 6 in the y value in any of the equations.

10x+10(6)=40 (Replaced 10y with 10(6) )

10x+60=40

-60 = -60 (Subtract 60 from both sides)

10x = -20 (Divide by 10 on both sides)

10 10

x = -2

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