Question

There was a plate of 2

mint brownies, 2 chocolate
brownies and 5 chocolate
brownies with nuts. What
is the probability that
Gavin will randomly take a
brownie with nuts,
put it back, and grab one
without nuts?

Answer 1

if you add the whole amount, then 2+2+5 is 9. then divide by 4 (the number without nuts) 4/9 is 44 percent

Explanation:

Answer 2

20/81

Explanation:

The total number of brownies is 2 + 2 + 5 = 9. The probability of Gavin taking a brownie with nuts on the first pick is 5/9. After putting it back, the total number of brownies is still 9, but the number of brownies with nuts is now 4. Therefore, the probability of Gavin taking a brownie without nuts on the second pick is 4/9. The probability of both events happening together is the product of the individual probabilities: (5/9) x (4/9) = 20/81. Therefore, the probability that Gavin will randomly take a brownie with nuts, put it back, and grab one without nuts is 20/81.