Answer:
X-intercept(s): (-3,0), (-8,0)
Y-intercept(s): (0,48)
Vertex: (-11/2,-25/2)
Explanation:
X-intercepts: When you are finding the x-intercepts, there are two ways to find your x-intercepts like you can find in the Quadratic Formula or plug the equation into your calculator and see it on the graph/ table. If you like the quadratic formula, you need plug into the a, b, and c and it will look like x= -22±√(22^2)-4(2)(48))/2(2). It will be the same answer. on the another hand, if you like the calculator way, you get your calculator that need be TI-84 plus CE or TI-84 then go on y= then put your equation like 2x^2+22x+48 after that you click on graph. if you cant find the x-intercepts on the graph, you can do 2nd then above the graph buttom you can see it in the table. When you looking at the table, look for the 0s in the y table.
Y-intercept: When you are finding the y-intercepts, there are two ways to find your y-intercepts like you need plug in 0 for x or plug the equation into your calculator and see it on the graph/ table. If you like the quadratic formula, you need plug in 0 for x and it will look like y=2(0)^2 +22(0)+48. it would the get the same answer. if you like the calculator way, you get your calculator that need be TI-84 plus CE or TI-84 then go on y= then put your equation like 2x^2+22x+48 after that you click on graph. if you cant find the x-intercepts on the graph, you can do 2nd then above the graph buttom you can see it in the table. When you looking at the table, look for the 0s in the x table.
Vertex:
1. Get your equation in the form like this y=ax^2+bx+c
2. Calculate -b/2a. This is the x-coordinate of the vertex.
3. To find the y- coordinate of the vertex, simply plug the x to the quadratic equation and solve for y.
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