Question

Which point is the vertex of the quadratic function f(x)=x^2-6x+8

Answer 1

(3, -1).

Explanation:

f(x)=x^2-6x+8

Convert to vertex form by completing the square:

f(x) = (x - 3)^2 - 9 + 8

= (x - 3)^2 -1

So the vertex is at (3, -1).