Question

a car is traveling 23 m/s the driver speeds up with an acceleration of 4.5 m/s^2. what is the final speed of the car 9 seconds later

Answer 1

63.5 m/s

Explanation:

u = 23 m/s

a = 4.5 m/s²

t = 9 sec

v = ?

`a = (v - u)/(t)`

`4 .5 = (v - 23)/(9)`

cross multiply

4.5 × 9 = v – 23

40.5 = v – 23

40.5 + 23 = v

v = 63.5

i hope this helps