Question

A net of a rectangular pyramid is shown.

A net of a rectangular pyramid with a base with dimensions of 14 inches by 17 inches. The two larger triangular faces have a height of 12 inches. The smaller triangular face has a height of 12.9 inches.

What is the surface area of the pyramid?

311.3 in2
384.6 in2
441.3 in2
622.6 in2

Answer 1

Answer: c

Explanation:

Cuz its c

Answer 2

The surface area of the rectangular pyramid can be calculated using the formula:

Surface area = (B + (4 x L))

Where B is the area of the base and L is the area of each side.

In this case, the area of the base is 14 x 17 = 238 in2 and the area of each side is 1/2 x 12 x 12.9 = 77.35 in2

Substituting these values into the formula, we get:

Surface area = (238 + (4 x 77.35)) = 441.3 in2.

Therefore, the surface area of the pyramid is 441.3 in2.