Answer:
91.2 g Mn
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
Step-by-step explanation:
Step 1: Define
[Given] 1.00 × 10²⁴ atoms Mn
Step 2: Identify Conversions
Avogadro's Numer
[PT] Molar Mass of Mn - 54.94 g/mol
Step 3: Convert
- [DA] Set up:
![\displaystyle 1.00 \cdot 10^(24) \ atoms \ Mn((1 \ mol \ Mn)/(6.022 \cdot 10^(23) \ atoms \ Mn))((54.94 \ g \ Mn)/(1 \ mol \ Mn))](https://img.qammunity.org/2022/formulas/chemistry/college/1s29kybcucqqhrsfq1yt5diet6n3uxnygs.png)
- [DA] Multiply/Divide [Cancel out units]:
![\displaystyle 91.2321 \ g \ Mn](https://img.qammunity.org/2022/formulas/chemistry/college/mcxfvee2p344qz43ky8hmahmhiewrj18vt.png)
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
91.2321 g Mn ≈ 91.2 g Mn