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What is the mass in grams of 1.00 x 10 24 atoms of Mn?

a)91.3 g
b) 123.4 g
c) 1.66 g
d) 166 g

User Jernej K
by
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2 Answers

4 votes
A.
Sana po makatulong sagot ko hehe
User Vishvadeep Singh
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4.6k points
7 votes

Answer:

91.2 g Mn

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

  • Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

[Given] 1.00 × 10²⁴ atoms Mn

Step 2: Identify Conversions

Avogadro's Numer

[PT] Molar Mass of Mn - 54.94 g/mol

Step 3: Convert

  1. [DA] Set up:
    \displaystyle 1.00 \cdot 10^(24) \ atoms \ Mn((1 \ mol \ Mn)/(6.022 \cdot 10^(23) \ atoms \ Mn))((54.94 \ g \ Mn)/(1 \ mol \ Mn))
  2. [DA] Multiply/Divide [Cancel out units]:
    \displaystyle 91.2321 \ g \ Mn

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

91.2321 g Mn ≈ 91.2 g Mn

User Joe Farrell
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5.6k points