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a 1920-kg car accelerates uniformly from rest to a speed of 15.0 m/s in 3.03 seconds. determine the average power (in hp) delivered by the engine during these 3.03 seconds. (1 hp

User TheWalker
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1 Answer

4 votes

Answer:

= 746 watts)

Step-by-step explanation:

The average power delivered by the engine can be calculated using the formula:

average power = work done / time taken

The work done on the car is equal to the change in its kinetic energy, which can be calculated using the formula:

ΔK = (1/2) * m * Δv^2

where m is the mass of the car, Δv is the change in velocity, and ΔK is the change in kinetic energy.

In this case, the mass of the car is 1920 kg, the initial velocity is zero, the final velocity is 15.0 m/s, and the time taken is 3.03 seconds. Therefore:

Δv = 15.0 m/s - 0 = 15.0 m/s

ΔK = (1/2) * 1920 kg * (15.0 m/s)^2 = 1,620,000 J

The time taken is given as 3.03 seconds.

Therefore, the average power delivered by the engine is:

average power = ΔK / time taken

average power = 1,620,000 J / 3.03 s

average power = 534653.47 W

Converting this to horsepower:

1 hp = 746 W

average power = 534653.47 W / 746 W/hp

average power = 716.33 hp

Therefore, the average power delivered by the engine is approximately 716.33 horsepower.

User Lhlmgr
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