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The volume of a right cone is 33\piπ units^3

3
. If its circumference measures 6\piπ units, find its height.

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Let's denote the radius of the cone as 'r' and the height as 'h'.

The formula for the volume of a cone is:

V = (1/3) * π * r^2 * h

And the formula for the circumference of the base of a cone is:

C = 2 * π * r

We know that the volume of the cone is 33π/3, so:

(1/3) * π * r^2 * h = 33π/3

Simplifying this equation, we get:

π * r^2 * h = 99π

r^2 * h = 99

We also know that the circumference of the base of the cone is 6π, so:

2 * π * r = 6π

Simplifying this equation, we get:

r = 3

Now we can substitute this value of 'r' into the equation we obtained earlier:

r^2 * h = 99

3^2 * h = 99

h = 11

Therefore, the height of the cone is 11 units.

User Anothershrubery
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