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For problems 3 and 4, state whether the given values of c and d create an equation with only one solution, infinitely many solutions, or no solution. 3, 5x+2= cx + d a. c= 5, d=5 b. c= 5, d=2 c. c = 2,
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Sep 9, 2024
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For problems 3 and 4, state whether the given values of c and d create an equation with only one
solution, infinitely many solutions, or no solution.
3, 5x+2= cx + d
a. c= 5, d=5
b. c= 5, d=2
c. c = 2, d = 5
Mathematics
high-school
Marian Zagoruiko
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Marian Zagoruiko
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a. No solutions
Substitute the Cs inside for 5 and Ds inside for 5.
5x + 2 = 5x + 5
Solve:
Subtract 5x from both sides
2 ≠ 5
Therefore, the answer for a is no solutions.
b. Infinitely many solutions
Now let’s substitute the Cs for 5 and the Ds for 2.
5x + 2 = 5x + 2
Solve:
Subtract 5x from both sides
2 = 2
So, the answer for b is infinitely many solutions
c. One solution
Let’s substitute the Cs for 2 and the Ds for 5.
5x + 2 = 2x + 5
Solve:
Subtract 2x from both sides
3x + 2 = 5
Now subtract 2 from both sides
3x = 3
Divide both sides by 3
x = 1
So the answer for c would be one solution.
Humkins
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Sep 14, 2024
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Humkins
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